A particle having a mass of 1.5 kg, moves along a three-dimensional path defined by the equations r = 94 + 3t) m, _{} = (t^{2} + 2) rad, and z = (6 - t^{3}) m, where t is in seconds, and the z-axis is vertical. Determine the r, _{}, and z components of force which the path exerts on the particle when t = 2 s.

[A].

F_{r} = 0, F_{2} = 30 N, F_{z} = -18.00 N

[B].

F_{r} = -240 N, F_{2} = 66.0 N, F_{z} = -3.29 N

[C].

F_{r} = 0, F_{2} = 3 N, F_{z} = -18.00 N

[D].

F_{r} = -160.0 N, F_{2} = 44.0 N, F_{z} = -12.00 N

Answer: Option B

Explanation:

No answer description available for this question.